Hi Group of 33: 15 Sr & 18 Jr Choose 8: 33C8 all the ways they can be chosen a. P(5 Sr & 3 Jr) = (15C5)(18C3)/ (33C8) b. P(at least 6 seniors) = P(6 Sr) + P(7 Sr) + P(8 Sr) P = [(15C6)(18C2) + (15C7)(18C1) + (15C8)(18C0)]/(33C8) Wish You the Best in your Studies.