SOLUTION: A company decides to send two people on a trip using either 2 men or 2 women. There are 8 men and 5 women eligible for the trip. How many ways are there to do this?

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Question 1177361: A company decides to send two people on a trip using either 2 men or 2 women. There are 8 men and 5 women eligible for the trip. How many ways are there to do this?
Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Previously Posted.
12 people:  8M  5F
chose two, either 2 men OR 2 women.
Ways of doing this:  8C2 + 5C2 = 28 + 10 = 38 ways

Wish You the Best in your Studies.

Answer by ikleyn(52909)   (Show Source): You can put this solution on YOUR website!
.

I solved this problem today earlier under this link

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1177353.html

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1177353.html



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