Hi !.= 20 i. = (500/20)^2 = 625 ii. ME = =25 25 = z*20 z = 25/20 = 1.25 and P (z ≤ 1.25) = .8944 2a. 1/SE = z = 1.7678 and P(z ≤ 1.7678) = .9615 The central limit theorem states that whenever a random sample of size n is taken from any distribution with mean and variance, then the sample mean will be approximately normally distributed with mean and variance We are proceeding as if the distribution of this sample(size 50)..its mean will be approximately normally distributed. Will let You finish up or repost your last question. Site asks that there be one question per post. Wish You the Best in your Studies.