Hi 1) Binomial Distribution: p = .6 and n = 4a) P(x = 4) = 4C4 (.6)^4(.4)^0 = .1296 0r TI: P(x = 4) = (4,.6,4) b) P( x = 0) = 4C0 9.60^0(.40)^4 = .0256 c) P( x ≥ 1) = 1 - P(x=0) = 1 - .0256 = .9744 2) Normal distribution: mean of 62 and a standard deviation of 8. P(64< x < 72) = normalcdf(64,72,62,8) = .2956 |Using TI that is: P(x ≤ 72) - P( x≤ 64) 0r P(z ≤ 10/8) - P(z ≤ 2/8) Using Calculator/ Table to complete either. Wish You the Best in your Studies.