Hi Previously submitted. Normal distribution: Using TI or similarly an inexpensive Casio fx-115 ES plus: area under the standard normal distribution curve(continuous) is the same as the Probability of the given z-score: P( |z| ≤ -2.31) is 2P(z ≤ -2.31) = 2(.0104) = .0208 or P( |z| ≤ -2.31) = 1 - P( -2.31 ≤ z ≤ 2.31) = 1 - normalcdf(-2.31,2.31) Wish You the Best in your Studies. Shown below is the positioning of |z| = 2.31 on the Standard Normal Curve