SOLUTION: According to the last census, 45% of working women held full time jobs in 2010. If a random sample of 50 working women is drawn, what is the probability that 19 or more hold full t

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Question 1175758: According to the last census, 45% of working women held full time jobs in 2010. If a random sample of 50 working women is drawn, what is the probability that 19 or more hold full time jobs?
Answer by ikleyn(52833)   (Show Source): You can put this solution on YOUR website!
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According to the last census, 45% of working women held full time jobs in 2010. If a random sample
of 50 working women is drawn, what is the probability that 19 or more hold full time jobs?
~~~~~~~~~~~~~~~~

It is a binomial distribution probability problem.

    - number of trials        n =  50;

    - number of success trial k >= 19;

    - Probability of success on a single trial p = 0.45.



We need calculate  P(n=50; k>=19; p=0.45) = 0.531441.      



To facilitate calculations, I use an appropriate online (free of charge) calculator at this web-site 

https://stattrek.com/online-calculator/binomial.aspx



It provides nice instructions  and  a convenient input and output for all relevant options/cases.


    P(n=50; k>=19; p=0.45) = 0.87265488533,   or   0.8727 (rounded).       ANSWER

Solved.

---------------

To see a variety of similar solved problems,  look into the lessons
    - Simple and simplest probability problems on Binomial distribution
    - Typical binomial distribution probability problems
    - How to calculate Binomial probabilities with Technology (using MS Excel)
    - Solving problems on Binomial distribution with Technology (using MS Excel)
    - Solving problems on Binomial distribution with Technology (using online solver)
in this site.

After reading these lessons,  you will be able to solve such problems on your own,
which is your  PRIMARY  MAJOR  GOAL  visiting this forum  (I believe).



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