SOLUTION: A Food Marketing Institute found that 26% of households spend more than $125 a week on groceries. Assume the population proportion is 0.26 and a simple random sample of 52 househol

Question 1175543: A Food Marketing Institute found that 26% of households spend more than $125 a week on groceries. Assume the population proportion is 0.26 and a simple random sample of 52 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is between 0.23 and 0.5?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
This is z (0.23-0.26)/sqrt(.26*.74/52)
=-0.49
and z (0.50-0.26)/sqrt(.26*.74/52)
=3.94
probability is 0.6879
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