Hi
1) Normal Distribution: the population standard deviation σ = 12.1 ounces
Sample Size is 33: Sample mean = 44
90% confidence Interval, find ME
ME = 1.645 (12.1)/√33 = 3.465
CI = 44 ± 3.465
2) Normal Distribution: Sample of 12 mean = 66.533 sd = 9.012
80% CI z = 1.362 df 11
ME == = 3.543
80% C.I. = (62.99,70.08)
Wish You the Best in your Studies.
Confidence Level 80% 90% 95% 98% 99%
Two-sided test p-values 0.2 0.1 0.05 0.02 0.01
One-sided test p-values 0.1 0.05 0.025 0.01 0.005
Degrees of Freedom (df=n-1)
1 3.078 6.314 12.71 31.82 63.66
2 1.886 2.92 4.303 6.965 9.925
3 1.638 2.353 3.182 4.541 5.841
4 1.533 2.132 2.776 3.747 4.604
5 1.476 2.015 2.571 3.365 4.032
6 1.44 1.943 2.447 3.143 3.707
7 1.415 1.895 2.365 2.998 3.499
8 1.397 1.86 2.306 2.896 3.355
9 1.383 1.833 2.262 2.821 3.25
10 1.372 1.812 2.228 2.764 3.169
11 1.362 1.796 2.201 2.718 3.106