Hi 4. population standard deviation σ=36.7 90% confident level ME =0r n = (t*sigma/ME)^2 n = [(1.96(36.7)/(.1)]^2 = 5. x̄ = 42 sd = 13 95% confidence level ME = ME = 2.201(13)/√12 |df = 11 (n-1) 42 - ME < < 42 + ME Wish You the Best in your Studies. Confidence Level 80% 90% 95% 98% 99% Two-sided test p-values 0.2 0.1 0.05 0.02 0.01 One-sided test p-values 0.1 0.05 0.025 0.01 0.005 Degrees of Freedom (df=n-1) 1 3.078 6.314 12.71 31.82 63.66 2 1.886 2.92 4.303 6.965 9.925 3 1.638 2.353 3.182 4.541 5.841 4 1.533 2.132 2.776 3.747 4.604 5 1.476 2.015 2.571 3.365 4.032 6 1.44 1.943 2.447 3.143 3.707 7 1.415 1.895 2.365 2.998 3.499 8 1.397 1.86 2.306 2.896 3.355 9 1.383 1.833 2.262 2.821 3.25 10 1.372 1.812 2.228 2.764 3.169 11 1.362 1.796 2.201 2.718 3.106