SOLUTION: A bag contains 10 blue, 6 red, and 4 green rubber balls. If you select a ball at random from the bag, what is the probability of not choosing a green ball? A. 1/5 B. 4/5 C.

Question 117457: A bag contains 10 blue, 6 red, and 4 green rubber balls. If you select a ball at random from the bag, what is the probability of not choosing a green ball?

A. 1/5
B. 4/5
C. 5/6
D. 9/10
Why can you eliminate choice D in this question?
Found 2 solutions by Edwin McCravy, Fombitz:
Answer by Edwin McCravy(20086) (Show Source): You can put this solution on YOUR website!

A bag contains 10 blue, 6 red, and 4 green rubber balls. If you select a ball at random from the bag, what is the probability of not choosing a green ball? A. 1/5 B. 4/5 C. 5/6 D. 9/10 To not choose a green ball means to select a non-green ball. There are 16 non-green balls out of the 20. So the probability is 16/20 which reduces to 4/5, so the correct answer is B. ---------------------------------------------------------- Why can you eliminate choice D in this question? Because that's what the answer would be if there had been 10 blue, 8 red, and 2 green rubber balls. Edwin

Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The total number of balls available is 10+6+4=20 balls.
The probability of choosing a blue ball is 10/20.
The probability of choosing a red ball is 6/20.
The probability of choosing a green ball is 4/20.
P(green or not green) = 1, since the ball I choose must be either green or not green.
P(green) + P(not green) = P(green or not green)
4/20 + P(not green) = 1
P(not green) = 16/20 = 4/5
The answer is B.
You can eliminate D because none of the probability can sum to 18 out of 20(9/10). The only possible choices are 16/20, 14/20, or 10/20.
You can also eliminate C because it's not possible to sum to repeating fraction from the possible probabilities (0.5,0.3,0.2).
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