SOLUTION: Assume someone gives you all the answers for an exam, but he/she does not tell you which answers correspond to which questions on the exam. Unfortunately your last 3 months were ju

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Question 1174437: Assume someone gives you all the answers for an exam, but he/she does not tell you which answers correspond to which questions on the exam. Unfortunately your last 3 months were just too busy to study for the exam and hence, to be able to conclude which answer goes where. If the exam has 6 questions, what are your chances to have exactly 4 answers correct, if you choose answers on random from the 6 you received and set them as answers to 1st, 2nd, 3rd , 4th, 5th and 6th question. (Give the probability in the form of a decimal number with 4 decimals (example: 0.1234)! )
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.

The total number of possible outcomes is  6*5*4*3*2 = 720.

    (the product of 5 sequential integer numbers starting from 6 in descending order).



It is because any of 6 answers can be in the first position,

              any of remaining 5 answers can be in the second position,

                     . . . and so on . . . 


It is the space of events.



Of these possible outcomes, ONLY ONE does match (!).


THEREFORE, the probability under the problem's question is  .     ANSWER

Solved and explained.

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After reading my post, do not forget to post your "THANKS" to me for my teaching (!)


Happy learning (!)



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