Hi,

In a large population, 64% of the people have been vaccinated.
If 4 people are randomly selected:              
 
what is the probability that at least one of them has been vaccinated?

  
P( x≥ 1) = 1 - binomcdf(4, .64, 0)  = 1 - .0168 = .983 (decimal to 3 places)
            
Wish You the Best in your Studies.
 Solution works Great... with proper entering.

This probability is the COMPLEMENT to the probability of the event "No one of 4 has been vaccinated",


and THEREFORE is equal to  1 -  =  = 0.9791.

I agree with tutor @IKLEYN that the other person is WRONG. I also agree with tutor @IKLEYN's setup of the problem, with the exception that

the success rate s/b 64% (.64) as opposed to 62% (.62), thereby making the answer: 0.98320384 ≈  

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