Hi,

Normal Distribution:  μ = 1020  and   σ = 153 

What should his score be on this test so that only 10% of 

all examinees score higher than he does?  z = -1.282 (represent 10%)





  Solve for x



  153(1.282) + 1020 = x = 1216 (rounded to nearest whole number)

   

Wish You the Best in your Studies.

 

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