SOLUTION: Five hundred children participated in a field demonstration. Their heights averaged 110 cm with a standard deviation of 6 cm. a. What is the probability/percentage that a child

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Question 1173707: Five hundred children participated in a field demonstration. Their heights averaged 110 cm with a standard deviation of 6 cm.
a. What is the probability/percentage that a child, picked at random has a height greater than 120 cm?
b. What is the probability/percentage that the height of a child, picked at random, is less than 100 cm?
c. Find the height such that 80% of the children are above it.
d. How many children belong to upper 40% of the group?

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Normal Distribution:
μ = 110 α = 6
Note: The -9999 is used as the smaller value to be at least 5 standard deviations from the mean.
Using a TI calculator 0r similarly a Casio fx-115 ES plus <$20)
a. What is the probability/percentage that a child, picked at random has a height greater than 120 cm?
P (x > 120 ) = 1 - P (x ≤ 120 ) | Continuous function
P (x > 120 ) = 1 - normalcdf(-9999,120,110,6) = 1 - .9522 = .0478
b. What is the probability/percentage that the height of a child, picked at random, is less than 100 cm?
P (x < 100 ) = P (x ≤ 100 ) |Continuous function
P (x < 100 ) = P (x ≤ 100 ) =normalcdf(-9999,100,110,6) = .04778
c. Find the height such that 80% of the children are above it
InvNorm( .8,6,110) = 115.0497
height > 115cm for those above the 80th percentile
d. How many children belong to upper 40% of the group?
invNorm( .6,6,110) = 111.5cm
height > 111.5cm for those to upper 40% of the group
Wish You the Best in your Studies.

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