SOLUTION: A survey of daily travel time had these results (in minutes):
The Mean is 38.8 minutes, and the Standard Deviation is 11.4 minutes.
Find the P(X<30) and P(30<X<45).
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Question 1172996: A survey of daily travel time had these results (in minutes):
The Mean is 38.8 minutes, and the Standard Deviation is 11.4 minutes.
Find the P(X<30) and P(30
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
P(30) is 0. Density function probabilities involve area, and a dimensionless point will have no area.
P(x< 30) is (30-38.8)/11.4
=-8.8/11.4 for z or -0.77
P( z< 0.77)=0.2201
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