Hi,
p = 1/2 , n = 10 , 5G, 5def
customer buys 6 laptops.
Probability of them being good or defective is the same
a) What is the probability of exactly 2 defective laptops among them?
P(2def) = (5C2)(5C4)/(10C6) = (10)(5)/(210)
b What is the probability of 3 defective and 3 good laptops among them
P(3 defective and 3 good laptops) = (5C3)(5C3)/(10C6) = (10)(10)/(210)
(a) In this case, the customer gets 2 defective and 6-2 = 4 good laptops. The probability to have this selection is P == = . (a) In this case, the customer gets 3 defective and 6-3 = 3 good laptops. The probability to have this selection is P = = =