SOLUTION: For 3 ensurance companies, the chances that a client closes an ensurance deal are 15%, 16% , 17%. Three clients enter simultaniously, one in each of the 3 companies. What's the pro

Question 1172795: For 3 ensurance companies, the chances that a client closes an ensurance deal are 15%, 16% , 17%. Three clients enter simultaniously, one in each of the 3 companies. What's the probability of?
1. 2 clients close an ensurance deal?
2. At least 2 clients close an ensurance deal?
Answer by ikleyn(52847) (Show Source): You can put this solution on YOUR website!
.
For 3 insurance companies, the chances that a client closes an insurance deal are 15%, 16% , 17%. T
Three clients enter simultaneously, one in each of the 3 companies. What's the probability of?
1. 2 clients close an insurance deal?
2. At least 2 clients close an insurance deal?
~~~~~~~~~~~~~~~~~

(1)  P = P(1st yes, 2nd yes, 3rd no) + P(1st yes, 2nd no, 3rd yes) + P(1st no, 2nd yes, 3rd yes) = 

       =   0.15   * 0.16*   (1-0.17) +   0.15 * (1-0.16) * 0.17    + (1-0.15) * 0.16   * 0.17    = 0.06446.   



(2)  P = P(1st yes, 2nd yes, 3rd no) + P(1st yes, 2nd no, 3rd yes) + P(1st no, 2nd yes, 3rd yes) +  P(all 3 yes)  = 

       =   0.15   * 0.16*   (1-0.17) +   0.15 * (1-0.16) * 0.17    + (1-0.15) * 0.16   * 0.17    + 0.15*0.16*0.17 = 0.06854.

Solved.

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