SOLUTION: How many people would you need in a group to ensure a 99.9% probability of two of them sharing the same birthday?

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Question 1172639: How many people would you need in a group to ensure a 99.9% probability of two of them sharing the same birthday?


Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
The formula for the number of comparisons between pairs of N people is:
(N*(N-1))/2.
At 1596 pairs for N = 57 (99% chance)
99.9% ?? my choice would be 60 people
Wish You the Best in your Studies.
.
Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.

For nice description of the  Birthday  Problem,  see this  Wikipedia article

https://en.wikipedia.org/wiki/Birthday_problem

https://en.wikipedia.org/wiki/Birthday_problem



For the  99.9%  probability,  this article gives the answer  70  people in the group.



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