SOLUTION: Of 288 employees randomly selected from one company, 14.6% of them commute by carpooling. Construct a 90% confidence interval for the true population proportion of all employees wh
Algebra ->
Probability-and-statistics
-> SOLUTION: Of 288 employees randomly selected from one company, 14.6% of them commute by carpooling. Construct a 90% confidence interval for the true population proportion of all employees wh
Log On
Question 1171711: Of 288 employees randomly selected from one company, 14.6% of them commute by carpooling. Construct a 90% confidence interval for the true population proportion of all employees who carpool. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! the half-interval iz z(0.95)*sqrt(p*(1-p)/n)
=1.645* sqrt (0.146*0.854)/288=0.0342
The 90%CI is (0.114, 0.178)
This assumes that 14.6% of 288 is an integer, which it almost is. The actual number is 42/288 but it gives the same result except at the thousandth place.
