SOLUTION: Suppose the number of children in a household has a binomial distribution
with parameters n = 10, and p = 30 %.
Find the probability of a household having:
(a) 0 or 6 children
Algebra.Com
Question 1171688: Suppose the number of children in a household has a binomial distribution
with parameters n = 10, and p = 30 %.
Find the probability of a household having:
(a) 0 or 6 children
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
The probability of 
successes in 
independent trials where the probability of success on any trial is 
is given by:
\ =\ {{n}\choose{k}}\(p\)^k\(1-p\)^{n-k})
For 0 or 6 successes out of 10 with a probability of 30%
You need to calculate: \ +\ P(6,10,0.3))
. You can do your own arithmetic.
John
My calculator said it, I believe it, that settles it
From
I > Ø
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