SOLUTION: At an ocean side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water that is discharged back into the ocean. The amount th

Question 1170605: At an ocean side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water that is discharged back into the ocean. The amount that the water temperature is raised has a uniform distribution over the interval from 10° to 25° C.
What is the probability that the temperature increase will be less than 20° C?
What is the probability that the temperature increase will be between 20° C and30^(0 ) C?

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
If this is a uniform function then there is a denominator of 15 degrees (25-10)
< 20 C would be < 10/15 or 2/3 or appropriate decimal.
Between 20 and 30 C is 5/15, and the part from 25-30 is outside the distribution and therefore is not considered. The probability is 1/3.
RELATED QUESTIONS
At an ocean side nuclear power plant, seawater is used as part of the cooling system.... (answered by Boreal)

A large cooling tower in the shape of a hyperboloid is used to remove the heat from a... (answered by CPhill)

I have a problem "The sides of a nuclear power plant cooling tower form a hyperbola. The... (answered by greenestamps)

The sides of a nuclear power plant cooling tower form a hyperbola. The diameter of the... (answered by greenestamps)

The sides of a nuclear power plant cooling tower form a hyperbola. The diameter of the... (answered by CPhill,ikleyn)

The sides of a nuclear power plant cooling tower form a hyperbola. The diameter of the... (answered by greenestamps)

the cross section of a nuclear power plant cooling tower is in the shape of a hyperbola.... (answered by lwsshak3)

the cross-section of a nuclear power plants cooling tower is in the shape of a hyperbola. (answered by solve_for_x)

22. Vapor Pressure Problem: The vapor pressure of water is the pressure that water vapor... (answered by stanbon)