SOLUTION: A smoke detector system uses two devices, A and B. Suppose the probability that it will be detected by device A is 0.95, the probability that it will be detected by device B is 0.9
Question 1169426: A smoke detector system uses two devices, A and B. Suppose the probability that it will be detected by device A is 0.95, the probability that it will be detected by device B is 0.90, and the probability that it will be detected by both devices is 0.89. What is the probability of the event that the smoke will be detected by device B alone? Express the question in notation and compute. Answer by ikleyn(52872) (Show Source): You can put this solution on YOUR website! .
P(B alone) = P(B) - P(B and A) = 0.9 - 0.89 = 0.01. ANSWER