SOLUTION: Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly s
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Question 1168871: Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -2.19°C and -0.419°C.
P(-2.19 < Z < -0.419) =
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
mean = 0 degrees centigrade
standard deviation is 1 degree centigrade.
probabilit y of obtaining a reading between -2.19 degrees centigrade and -.419 degrees centigrade is ?????
use the following calculator.
https://stattrek.com/online-calculator/normal.aspx
this calculator works similar to the tables, i.e. it just gives you the area to the left of the z-score or x-score and you have to figure out the rest, i.e. like finding the area to the right of the z-score by finding the area to the left of the z-score and then subtracting it from 1.
for the low score, set p(x
calculator says probability is .014.
the the high score, set p(x
calculate says probability is 0.338
subtract the smaller area from the larger area to get:
area between -2.19 and -.419 = .338 minus .014 = .324
visually, this looks like this:
the different values you see are due to rounding differences between the calculators used.
the calculator that gave you the visual display can be found at:
http://davidmlane.com/hyperstat/z_table.html
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