SOLUTION: A restaurant has a lunch special that allows you to chose 1 meat and 1 vegetable for $2.99. You order a food from the restaurant above and tell them to pick any meat and vegetable.

Question 1167766: A restaurant has a lunch special that allows you to chose 1 meat and 1 vegetable for $2.99. You order a food from the restaurant above and tell them to pick any meat and vegetable.
(1) How many ways can you select a meat and then a vegetable from roast, fish, or chicken; and then peas, beans, or squash.
(2) What is the probability that they pick your favorite meal of chicken and beans?
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
.


(1)  Three options for meat and three independent options for vegetable.


     In all,  3 * 3 = 9  different outcomes are possible.

     (the fundamental counting principle).




(2)  Your favorite combination is one specific of 9 possible.


     The probability is  .

Solved.

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On fundamental counting principle, see the lesson
- Fundamental counting principle problems
in this site.

The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".

Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.

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