SOLUTION: A random sample of 20 acres gave a mean yield of sugarcane equal to 41.2 tons per acre with a standard deviation of 3 tons. Assuming that the yield of sugarcane per acre is normal

Question 1167758: A random sample of 20 acres gave a mean yield of sugarcane equal to 41.2 tons per acre with a
standard deviation of 3 tons. Assuming that the yield of sugarcane per acre is normally
distributed,
a. Construct a 90% confidence interval for the population mean.
b. What is the margin of error for this estimate in part a?

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
90% CI half-interval for a sample of 20 is t(0.95, df=19)* s/sqrt(n)
=1.729*3/sqrt(20)=1.16 tons/acre. This is the margin of error.
the 90% CI is (40.04, 42.36) units tons/acre
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