SOLUTION: Hi, if you can help me with this problem, it would be greatly appreciated! Thank you in advance! A sample of 100 clients of an exercise facility was selected. Let X = the number

Question 1166991: Hi, if you can help me with this problem, it would be greatly appreciated! Thank you in advance!
A sample of 100 clients of an exercise facility was selected. Let X = the number of days per week that a randomly selected client uses the exercise facility.
X Frequency
0 2
1 13
2 31
3 29
4 11
5 7
6 7
Find the number that is 1.5 standard deviations BELOW the mean. (I also have to round the answer to three decimal places.)
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
i get:
mean = 2.848485 rounded to 6 decimal places.
standard deviation = 1.416835 rounded to 6 decimal places.

1.5 standard deviations below the mean would be equal to:

2.848485 - 1.5 * 1.416835 = .7232325

round that to 3 decimal places to get .723.

the derivation of the mean and the standard deviation is shown below:

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