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The following table contains a break-down on the age and gender of mid-level managers in one company in Toronto.
Age in years
under 35 35-44 45-54 55-64 over 64 Total
Male 6 13 5 6 8 38
Female 1 9 9 20 20 59
Total 7 22 14 26 28 97
What is the probability that a randomly selected manager is neither female, nor 35-44 years old?
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You are very lucky person, because they just did part of the work for you.
In any case, you just have the total number of managers (97) to put it into the denominator of the fraction.
To find the numerator, subtract from the total 97 the total number of female managers 59
and then subtract the number 13 of male managers whose age is between 35-44.
So, your answer should be P =
.
I hope that everything is so clear that you do not need further explanations, right ?
Now use your calculator.
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Special THANKS to you for very accurate preparing/formatting the input data to this problem.