SOLUTION: Question # 3: the same physical fitness test was given to a group of 100 scouts and to a group of 144 guides. The maximum score was 30. The guides obtained a mean score of 26.81 an

Question 1166219: Question # 3: the same physical fitness test was given to a group of 100 scouts and to a group of 144 guides. The maximum score was 30. The guides obtained a mean score of 26.81 and the scouts obtained a mean of 27.53. Assuming that the fitness scores are normally distributed with a common population standard deviation of 3.48, test at the 5% level of significance whether the guides did not do as well as the scouts in the fitness test.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
2 sample z-test since sd known
critical value is |z|>1.96
z=(mean1-mean 2)sqrt (sigma^2((1/n1)+(1/n2))
=-0.72 /0.4529
=-1.59
fail to reject so insufficient evidence there is a difference.
p-value=0.12
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