SOLUTION: Can someone help me figure out how to solve this.
A university class has 22 students: 3 are nursing majors, 9 are accounting majors, and 10 are history majors.
The professor
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Question 1165657: Can someone help me figure out how to solve this.
A university class has 22 students: 3 are nursing majors, 9 are accounting majors, and 10 are history majors.
The professor is planning to select two of the students for a demonstration. The first student will be selected at random, and then the second student will be selected at random from the remaining students.
What is the probability that the first student selected is a nursing major and the second student is an accounting major?
Do not round your intermediate computations. Round your final answer to three decimal places.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
you have:
3 nursing majors
9 accounting majors
10 history majors
there are 22 total students.
the probability that the first student, selected at random, is a nursing student is 3/22.
the probability that the second student, selected at random from the remaining students, is an accounting major is 9/21.
the probability the first student chosen is a nursing student and the second student chosen is an accounting major is therefore 3/22 * 9/21 = 27/462.
in decimal form rounded to 3 decimal places, that is equal to .058.
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