I'll get you started.  You should be able to complete this problem using the information provided below.



There are four 7's available for the first pick.  There are also 52 cards from which to pick:  P(first draw is a 7) = 4/52



Now on the 2nd draw, there are three 7's available.  How many cards remain in the deck?   51, right.   P(2nd draw is also a 7) = 3/51



Apply this logic for the 3rd 7, then compute the total probability by MULTIPLYING the three fractions, perhaps simplifying fractions where possible.  

 

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
 without repetition?

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What does that mean? 

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