SOLUTION: Approximately 20% of corporate workforce are not happy with their immediate
bosses. Suppose 10 workers working in corporates are randomly selected.
a) What is the probability tha
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Question 1164775: Approximately 20% of corporate workforce are not happy with their immediate
bosses. Suppose 10 workers working in corporates are randomly selected.
a) What is the probability that everybody of them is happy with his immediate
boss?
b) What is the probability that at least two of the workers are unhappy with
their immediate bosses?
c) What is the probability that no more than two of the workers are unhappy
with their immediate bosses?
d) Calculate the expected value and variance of the distribution
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
.80 are happy so for all 10 to be happy is .80^10=0.1074
at least 2 are unhappy.
We know the probability that 0 are unhappy
probability that 1 is unhappy is 10*0.2*0.8^9=0.2684
so the probability that at least 2 are unhappy is 1-0.1074-0.2684=0.6242
the probability that no more than 2 workers are unhappy is the probability 0 are+prob 1 is+prob 2 are.
We know the first two. The probability that 2 are is 10C2*0.2^2*0.8^8=0.3020
The answer is 0.6778. Also on calculator with bincomcdf(10,0.2,2)ENTER
expected value depends upon whether we are talking about happy (np=8) or unhappy (np=2) workers
variance is the same for both (np(1-p))=1.6 workers
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