SOLUTION: The angles of an irregular polygon (Pentagon) are in the ratio of 3:5:6:7:9 find all the angles.

Algebra.Com
Question 1164675: The angles of an irregular polygon (Pentagon) are in the ratio of 3:5:6:7:9 find all the angles.
Answer by ikleyn(52908)   (Show Source): You can put this solution on YOUR website!
.

The angles are  3x, 5x, 6x, 7x, 9x,  where x is their common measure.


Then  3x + 5x + 6x + 7x + 9x = 30x = 180*(5-2) = 180*3  degrees.


Hence,  x =  = 6*3 = 18 degrees.


From this point, restore the angles on your own.

Solved.



RELATED QUESTIONS

Interior angles of a pentagon are in the ratio 4:5:6:7:5.find each angles of the pentagon (answered by Alan3354)
The interior angles of a Pentagon are in the ratio of4:8:6:4:5.find angles of the... (answered by josgarithmetic)
the angles of convex pentagon are in ratio 2:3:5:9:11 find measure of each... (answered by solver91311)
here are two angles of an irregular polygon 145 and 155 the no. of 155 angles is... (answered by ikleyn)
Four interior angles of a certain irregular pentagon are 38*, 96*, 112*, and 133*. Find... (answered by doukungfoo)
please help solve this: If the measure of the interior angles of a pentagon are in the... (answered by FrankM)
The angles of a Pentagon are in the rati 2:3:5:12. Find the largest and the smallest... (answered by ikleyn)
In an irregular polygon of n side,one of the interior angles is 60 degrees .if the other... (answered by Edwin McCravy)
1. The exterior angle of a pentagon are in the ratio 2:1:4:3:5 Find each angel of... (answered by greenestamps,ikleyn)