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Wording seems to be complicated, but the problem is, actually, quite simple.
With 4 switches, each of which can be in any of the two possible positions,
there are = 16 different setting for the control.
So, the probability for every one single of 4 neighbors to have the same setting in his (or her) control is
(their controls are of the same construction (!) ).
The probability that NO ONE of 4 neighbors has the same setting is .
The probability under the question is the COMPLEMENT to it, i.e.
P = 1 - = 1 - 0.7225 = 0.2275. ANSWER
Solved.
Very nice probability problem (!)
Hope that I correctly use the technical terms in my post . . .
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