SOLUTION: Five families each have two daughters and no sons. Assuming boy and girl babies are equally​ likely, what is the probability of this​ event?

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Question 1164179: Five families each have two daughters and no sons. Assuming boy and girl babies are equally​ likely, what is the probability of this​ event?
Answer by Edwin McCravy(20063)   (Show Source): You can put this solution on YOUR website!
For each family:

 X   p(X)
BB   1/4
BG   1/4
GB   1/4
GG   1/4

1/4 of the time the first family will have two girls, 
and 1/4 of those times the second family will also have two girls. 
Then 1/4 of those times the third family will also have two girls.
Then 1/4 of those times the fourth family will also have two girls. 
Then 1/4 of those times the fifth family will also have two girls.

That's (1/4)(1/4)(1/4)(1/4)(1/4) = (1/4)5 = 1/45 = 1/1024.

Edwin
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