SOLUTION: For this problem find the mean as well as the Standard Deviation.
X 0 1 2 3 4
P(x) .07 .20 .38
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Question 1162376: For this problem find the mean as well as the Standard Deviation.
X 0 1 2 3 4
P(x) .07 .20 .38 .22 .13
I was able to get the mean by using formula X= xp(x)=0(0.7)+1(.20) +2(.38) +3 (.22) +4(.13) which added all together gave me a mean of 2.14
For the standard deviation I keep getting confused on whether or not I'm inputting it correctly and cannot get the answer (0-2.14) squared(0) + (1-2.14) squared (.20) + (2-2.14)Squared and I just don't think I'm doing it right can you help me solve this last half please?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
To get the Standard Deviation, first calculate the Variance
\ =\ \(\sum\,x^2(P(x))\)\ -\ \mu^2)
Then the Standard Deviation is the square root of the variance.
John
My calculator said it, I believe it, that settles it
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