SOLUTION: Among the class of 100 students, 75 studied Botany, 55 studied Biology and 40 students studied both of the subjects. A student is selected at random from this class what is the p

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Question 1162354: Among the class of 100 students, 75 studied Botany, 55 studied Biology and 40 students
studied both of the subjects. A student is selected at random from this class what is the
probability that
i) student studied at least one subject
ii) student studied Botany but not Biology
iii) student studied Biology but not Botany
iv) student studied none of the subjects

Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!



Among the class of 100 students,
 
So a+b+c+d = 100
75 studied Botany,
 
So a+b = 75
55 studied Biology
 
So b+c = 55
and 40 students studied both of the subjects.
 
So b=40

Substituting 40 for b in b+c = 55
                        40+c = 55
                           c = 15

Substituting 40 for b in a+b = 75
                        a+40 = 75
                           a = 35

Substituting a=35, b=40, and c=15 in
                     a+b+c+d = 100
                  35+40+15+d = 100
                        90+d = 100
                           d = 10


A student is selected at random from this class what is the
probability that
i) student studied at least one subject
All but the 10.  So that's 100-10 = 90 out of 100, so the probability
is 90/100 which reduces to 9/10
ii) student studied Botany but not Biology
That's the 35.  So that's 35 out of 100, so the probability
is 35/100 which reduces to 7/20
iii) student studied Biology but not Botany.
That's the 15.  So that's 15 out of 100, so the probability
is 15/100 which reduces to 3/20
iv) student studied none of the subjects
That's the 10 that aren't in either circle.  So that's 10 out of 100, 
so the probability is 10/100 which reduces to 1/10.

Edwin

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