SOLUTION: Three cards are drawn without replacement from an ordinary deck of 52 playing cards. A fourth card is flipped, and known: the 6 of clubs.
The three cards are played in order. Wh
Algebra.Com
Question 1162348: Three cards are drawn without replacement from an ordinary deck of 52 playing cards. A fourth card is flipped, and known: the 6 of clubs.
The three cards are played in order. What is the probability that the first card played is either the 2 of hearts, 2 of spades or 2 of diamonds; the second card played is the 3 of the same suit as the first card played, and the third card played is neither a club nor a heart.
Would the answer be: (3/51)*(1/50)*(26/49) = 0.00062425
Thanks
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
See Ed McCravy's answer to problem 1162347.
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
Three cards are drawn without replacement from an ordinary deck of 52 playing cards. A... (answered by Edwin McCravy)
)
Three cards are drawn without replacement from an ordinary deck of 52 playing... (answered by richard1234)
Three cards are drawn without replacement from an ordinary deck of 52 playing cards. What (answered by stanbon,richard1234,filboi)
Three cards are drawn without replacement from an ordinary deck of 52 playing cards. A... (answered by greenestamps)
Need Help With This Problem... Thank You!!
9. Two cards are drawn without replacement... (answered by josmiceli)
Three cards are drawn from an ordinary deck of 52 cards without replacement. What is the... (answered by checkley77,edjones)
Two cards are drawn without replacement from an ordinary deck of 52 playing cards. What... (answered by checkley77,MathTherapy)
three cards are drawn without replacement from a well shuffled deck of 52 playing cards... (answered by ewatrrr)
Three cards are drawn without replacement from a well-shuffled deck of 52 playing cards.... (answered by stanbon)