SOLUTION: Past surveys reveal that 40% of Florida winter vacationers spend more than $3000 per month on accommodation. Florida tourism wants to update this information. Using the 90% confide

Algebra.Com
Question 1162075: Past surveys reveal that 40% of Florida winter vacationers spend more than $3000 per month on accommodation. Florida tourism wants to update this information. Using the 90% confidence level and an error of 5%, what is the necessary sample size?
Please could you help me with the correct answer and the explanation?
Thank you
Mean 3000
E 0,40
z = 1,645
p = 0,5
n = 4,2282E+00

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
half-interval is z*sqrt(0.40*0.60/n)=0.05
z=1.645
square both sides, move the n to the right and 0.05 to the denominator on the left.
2.706*0.24/0.0025=n=259.77 or 260 people

RELATED QUESTIONS

Past surveys reveal that 30% of tourists going to Las Vegas to gamble spend more than... (answered by stanbon)
Please help! Of the total population of older Americans, 18% live in Florida. For a... (answered by stanbon)
A rental property management company wants to estimate, with 99% confidence, the... (answered by ewatrrr)
Past surveys reveal that 30% of tourists going to Las Vegas to gamble spend more than... (answered by Boreal)
13.) Of the total population of older Americans, 18% live in Florida. For a randomly... (answered by stanbon)
The Amtrak auto train travels nonstop from lorton, Virginia to sanford, Florida. June... (answered by lwsshak3)
Hi On 10/03/13 I start College Algebra for State of Florida requirement for Culinary... (answered by Alan3354)
at the beginning of each month, the president of a small manufacturing company decides... (answered by Boreal)
List the values of n, p, and q in the following binomial experiment. According to a (answered by stanbon)