SOLUTION: if P(Ace)=4/52 ,P(Heart)=13/52 . P(Ace and Heart)=1/52 , then find P(Ace or Heart)?
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Question 1161629: if P(Ace)=4/52 ,P(Heart)=13/52 . P(Ace and Heart)=1/52 , then find P(Ace or Heart)?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
For non-mutually exclusive events:
\ =\ P(A)\ +\ P(B)\ -\ P(A\ \text{and}\ B))
John
My calculator said it, I believe it, that settles it
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