SOLUTION: Which sequence could be described by the recursive definition: tn+1 = -1 ⋅ tn + 3 A. 9, 6, -3, 0, 3,.... B. 8, 5, -2, 3, 0, ... C. 5, 2, 1, -2, -5, ... D. 4, -1, 4, -

Algebra.Com
Question 1161219: Which sequence could be described by the recursive definition: tn+1 = -1 ⋅ tn + 3
A. 9, 6, -3, 0, 3,....
B. 8, 5, -2, 3, 0, ...
C. 5, 2, 1, -2, -5, ...
D. 4, -1, 4, -1, 4, ....

The question for the sequence and the question itself is provided in the link here: https://i.imgur.com/6z88dty.png

Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.

            I have three questions.


1)  Do you understand the assignment in full ?


2)  If you do understand it in full, why don't you make it on your own ?


3)  If you do not understand some parts of the assignment, which exactly part do you not understand ?


It does not require to invent something.

It only requires to make calculations and to compare your results with the given numbers.

It is not a job for tutors.

Making these simple calculations is   YOUR   job.



RELATED QUESTIONS

Which sequence could be described by the recursive definition: tn+1 = -1 ⋅ tn + 3 A. (answered by solver91311)
Which sequence could be described by the recursive definition: tn+1 = -1 ⋅ tn + 3 A. (answered by MathLover1)
The Lucas numbers are defined by the recursive formula t1 = 2, t2 = 1, tn = tn - 1 + tn - (answered by Fombitz)
1. If tn=2n-3, for what value of 'n'is tn=5? Is it -1,1,4 OR 7??????? I think the... (answered by stanbon,gonzo)
A sequence Tn is defined by T1 = T2 = 1 and T(n+2) = T(n+1) + Tn Tn = {{{(a^n - b^n)/... (answered by ikleyn)
use the following recursive formula to write the first five terms of the sequence..... (answered by richard1234)
The n^th term, tn of a series:5/6+19/36+65/216+....... is given by Tn=a(1/2)^n+b(1/3)^n:... (answered by richwmiller,ikleyn)
Which of the following sequence can be the degree sequence of a graph ? (a) 5 , 3 , 2... (answered by ikleyn)
Which of the following sets of numbers follow a sequence? a.0.5,1,1.3,1.4... (answered by ikleyn)