SOLUTION: A housewife purchases 5 liters of milk, 3 loaves of bread and 6 cans of tuna. She gives the cashier R200 and receives R54 change.
How much did all the items cost?
If a liter
Question 1160938: A housewife purchases 5 liters of milk, 3 loaves of bread and 6 cans of tuna. She gives the cashier R200 and receives R54 change.
How much did all the items cost?
If a liter of milk costs R5 more than a can of tuna and a loaf of bread costs R2 less than a liter of milk, determine the cost of each item? Found 3 solutions by Theo, josgarithmetic, saw:Answer by Theo(13342) (Show Source): You can put this solution on YOUR website! all the items cost 200 minus 54 = 146.
all of the money is in R$, so 146 means R146.
1 liter of milk costs 5 more than a can of tuna.
1 loaf of bread costs 2 less than a liter of milk.
the housewife purchases 5 liters of milk, 3 loaves of bread, and 6 cans of tuna.
let M equal the cost of a liter of milk.
let T equal the cost of a can of tuna.
let B equal the cost of a loaf of bread.
you get:
5M + 3B + 6T = 146.
a liter of milk costs 5 more than a can of tuna and a loaf of bread costs 2 less than a liter of milk, therefore:
M = T + 5.
B = M - 2.
from the first of these two equations, solve for T to get:
T = M - 5
the two equations become:
T = M - 5
B = M - 2
the equation of 5M + 3B + 6T = 146 becomes:
5M + 3(M-2) + 6(M-5) = 146
simplify to get:
5M + 3M - 6 + 6M - 30 = 146
combine like terms to get:
14M - 36 = 146
add 36 to both sides of the equation to get:
14M = 182
solve for M to get:
M = 182 / 14 = 13
since T = M - 5, then T = 8
since B = M - 2, then B = 11
your original equation is 5M + 3B + 6T = 146.
this becomes 5*13 + 3*11 + 6*8 = 146 which becomes 146 = 146, confirming the solution is correct.
your solution is:
the cost of a liter of milk is R13.
the cost of a loaf of bread is R11.
the cost of a can of tuna is R8.
PRICE QUANTITY COST
Milk p+5 5
Bread (p+5)-2 3
Tuna p 6
TOTAL 146
You should be able to fill other information, form an equation, and solve the problem. Answer by saw(34) (Show Source): You can put this solution on YOUR website! Let m = a liter of milk
Let b = a loaf of bread
Let t = a can of tuna
5m+3b+6t = R200-R54 = R146
If a liter of milk costs R5 more than a can of tuna
m = t+5
If a loaf of bread costs R2 less than a liter of milk
b = m-2
5m+3b+6t = 146
5(t+5)+3(m-2)+6t = 146
5t+25+3m-6+6t = 146
11t+3(t+5)+19 = 146
11t+3t+15+19 = 146
14t+34 = 146
14t = 112
t = 8
m = 13
b = 11
A liter of milk costs R13 and 5 liters of milk costs R65.
A loaf of bread costs R11 and 3 loaves of bread costs R33.
A can of tuna costs R8 and 6 cans of tuna costs R48.
Check-----
5m+3b+6t = R146