SOLUTION: Is it A? I want to check my answers.
Which graph below has an EULER CIRCUIT?
C.
B.
D.
A.
The graph for the question and answer choices are in the link here: https
Algebra.Com
Question 1160716: Is it A? I want to check my answers.
Which graph below has an EULER CIRCUIT?
C.
B.
D.
A.
The graph for the question and answer choices are in the link here: https://i.imgur.com/9IDGAIN.png
Found 3 solutions by solver91311, jim_thompson5910, math_helper:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
A graph with 2 or less odd vertices has an Euler Circuit.
John
My calculator said it, I believe it, that settles it
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Yes you are correct. The answer is graph A.
One possible Euler circuit is to start at A and follow the exact sequence in the order shown below
ABC,DEF,CEB,FA
I used commas to make the sequence more readable
To be honest, that is potentially a jumble of letters to easily get lost in. It might be easier to label the segments in the order they are used. These are the numbers shown in red
The blue and green paths are to help separate the overlapping portions.
Side note: If you use every edge exactly one time, but don't necessarily end up at the same starting point, then you have followed an Euler path. An Euler circuit is an Euler path that ends up at the same starting point. You can picture the edges as a series of bridges. Each time you use a bridge, the bridge breaks (from weight or perhaps it was burned somehow) so you cannot use that bridge again. The goal is to use all bridges and end up at the same starting point.
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
Yes, (A) has an Euler circuit (to have an Euler circuit, every vertex must have even degree, or put another way, the number of verticies with odd degree must be zero).
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