SOLUTION: In 2006, 86% of U.S. households had cable TV. Choose 3 households at random. Find the probability that, a. None of the 3 households had cable TV. b. All 3 households had cable TV

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Question 1160651: In 2006, 86% of U.S. households had cable TV. Choose 3 households at random. Find the probability that,
a. None of the 3 households had cable TV.
b. All 3 households had cable TV.
c. At least 1 of the 3 households had cable TV.
Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.

(a)  P =  =  = 0.002744.



(b)  P =  = 0.636056.



(c)  P = 1 -  = 1 - 0.002744 = 0.997256.

Solved.

All formulas are self-explanatory.



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