You can
put this solution on YOUR website! P( A ) = 0.5
P( B ) = 0.8
P( A ᑎ B ) = 0.3
Solve this question
1. P ( A | A ᑎ B )
2. P ( A ᑎ B | A ᑌ B )
The formula for conditional probability is
P( X ᑎ Y )
P( X | Y ) = ————————————
P( Y )
1. P ( A | A ᑎ B )
Substitute A for X and A ᑎ B for Y
P[ A ᑎ (A ᑎ B) ] P[ (A ᑎ A) ᑎ B ] P( A ᑎ B )
P ( A | A ᑎ B ) = ————————————————— = ————————————————— = ——————————— = 1
P( A ᑎ B ) P( A ᑎ B ) P( A ᑎ B )
It is certain that you are given A if you are given A and B.
It doesn't even matter what the probabilities for A, B are.
2. P ( A ᑎ B | A ᑌ B )
Substitute A ᑎ B for X and A ᑌ B for Y
P[(A ᑎ B) ᑎ (A ᑌ B) ]
P( A ᑎ B | A ᑌ B ) = ——————————————————————
P( A ᑌ B )
We simplify
(A ᑎ B) ᑎ (A ᑌ B) = [(A ᑎ B) ᑎ A] ᑌ [(A ᑎ B) ᑎ B] =
[A ᑎ (B ᑎ A)] ᑌ [A ᑎ (B ᑎ B)] = [A ᑎ (A ᑎ B)] ᑌ (A ᑎ B) =
[(A ᑎ A) ᑎ B)] ᑌ (A ᑎ B) = (A ᑎ B) ᑌ (A ᑎ B) = A ᑎ B
The formula for
P( X ᑌ Y ) = P( X ) + P( Y ) - P( X ᑎ Y )
P( A ᑌ B ) = P( A ) + P( B ) - P( A ᑎ B )
P( A ᑌ B ) = 0.5 + 0.8 - 0.3 = 1
P( A ᑎ B ) 0.3
P( A ᑎ B | A ᑌ B ) = ————————————— = ———— = 0.3
P( A ᑌ B ) 1
Edwin