SOLUTION: The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 3.5. Suppose 49 golfers played the course today. Find the probability that the
Algebra.Com
Question 1159294: The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 3.5. Suppose 49 golfers played the course today. Find the probability that the average score of the 49 golfers exceed 76.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
z=(x-mean)/sd/sqrt(n)
z>=(76-75)/3.5/sqrt(49)
>=7/3.5=2
That probability of z>2 is 0.0228
RELATED QUESTIONS
the average score of all golfers for a particular course has a mean of 76 and a standard... (answered by Boreal)
3 ) The average score of all golfers for a particular course has a mean of 66 and a... (answered by ewatrrr)
the average score of all golfers for a particular course has a mean of 80 and a standard... (answered by stanbon)
The average score for all pro golfers for a particular course has a mean of 70 and a... (answered by stanbon)
The average score of all pro golfers for a particular course has a mean of 70 and a... (answered by ewatrrr)
The average score of all pro golfers for a particular course has a mean of 70 and a... (answered by stanbon)
a sample of 85 golfers showed that their average score on a particular golfers course was (answered by stanbon)
. A sample of 40 golfers showed that their average score on a particular golf course was... (answered by trelle)
A sample of 106 golfers showed that their average score on a particular golf course was... (answered by stanbon)