SOLUTION: A local concert center reports that it has been experiencing a 15% rate of no-shows on advanced reservations. Among 150 advanced reservations, find the probability that there will

Question 1159166: A local concert center reports that it has been experiencing a 15% rate of no-shows on advanced reservations. Among 150 advanced reservations, find the probability that there will be fewer than 20 no-shows. Round the standard deviation to three decimal places to work the problem.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
mean is 150*0.15=22.5
variance is np(1-p)=22.5*0.85=19.125
sd is sqrt (V)=4.373
fewer than 20 no shows means < 19.5 using continuity correction factor
z<(19.5-22.5)/4.373
z<-0.686
that probability is 0.2464
(exact is 0.2509)
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