SOLUTION: A surgery conducted that asked 1015 people how many books they had read in the last year. Results indicated that x=13.7 and s=16.6 books. Construct a 99% confidence interval for th
Algebra.Com
Question 1157945: A surgery conducted that asked 1015 people how many books they had read in the last year. Results indicated that x=13.7 and s=16.6 books. Construct a 99% confidence interval for the mean number of books people read. Interpret the interval
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
the 99%CI half-interval is t(0.995,df=1015)*s/sqrt(n). {it is a survey}
=2.581*16.6/sqrt(1015)
=1.34
the interval is (12.36, 15.04)
probably should round to (12.4, 15.0) units books
That means while we don't know the average number of books all people have read in the past year, we are 99% confident that the true number lies in the interval (12.4, 15.0)
RELATED QUESTIONS
A poll was conducted that asked 1014 people how many books they had read in the past... (answered by Boreal)
Hello, i am having a bit of a problem that i am struggling with. I was wondering can you... (answered by jim_thompson5910)
a survey was conducted that asked 1003 people how many books they had read in the past... (answered by stanbon)
A survey was conducted that asked 1077 people how many books they had read in the past... (answered by rothauserc)
9.2 #16
People were polled on how many books they read the previous year. Initial survey (answered by Boreal)
People were polled on how many books they read the previous year. How many subjects are... (answered by Boreal)
People were polled on how many books they read the previous year. How many subjects are... (answered by Boreal)
People were polled on how many book they read the previous year. How many subjects are... (answered by stanbon)
people were polled on how many books they read the previous year. How many subjects are... (answered by Susan-math)