There are 4 aces in a deck of 52.  So about 4/52nds or 1/13th of the time you
will draw an ace the first time.

When you do draw an ace the first time, you will have a deck of 51 with only 3
aces.  So 3/51 or 1/17th of those 1/13ths of the time when you draw an ace on
the first draw, you will also draw an ace on the second draw.

So 1/17th of those 1/13ths of the time when you drew an ace on the first draw,
you will also draw an ace on the second draw.

So 1/17th of 1/13ths of the time is (1/13)×(1/17) = 1/221sts of the time.

So the probability of drawing two aces in a row without replacement is 1/221.

So you'll have to draw two cards every morning for 221 days, to be able to
expect that 1 of those 221 days you'll draw two aces in a row.

Answer: 1/221

Edwin