SOLUTION: n a survey of 1053 1053 people, 780 780 people said they voted in a recent presidential election. Voting records show that 71 71% of eligible voters actually did vot

Question 1156449: n a survey of
1053
1053 people,
780
780 people said they voted in a recent presidential election. Voting records show that
71
71% of eligible voters actually did vote. Given that
71
71% of eligible voters actually did vote, (a) find the probability that among
1053
1053 randomly selected voters, at least
780
780 actually did vote. (b) What do the results from part (a) suggest?
(a) P(X
greater than or equals
≥
780
780)
equals
=
nothing
(Round to four decimal places as needed.)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
the point estimate is 0.7407
one tail test with a z-value = 0.7407-0.71)/sqrt (0.71*0.29/1053)
that equals 2.195
that probability is 0.0140 rounding at end.
The results suggest that it is unlikely to get this sort of result if the true value were 71%. Therefore, the true value is likely more than 71%.
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SOLUTION: n a survey of 1053 1053 ​people, 780 780 people said they voted in a recent presidential election. Voting records show that 71 71​% of eligible voters actually did vot

SOLUTION: n a survey of 1053 1053 people, 780 780 people said they voted in a recent presidential election. Voting records show that 71 71% of eligible voters actually did vot