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The probability to get the sum 6 tossing a pair of dice is .
// Simply because there are 5 favorable pairs (1,5), (2,4) (3,3) (4,2) (5,1) of 36 possible outcomes.
Hence, the probability DO NOT get the sum 6 tossing a pair of dice is the complement .
Now, the problem asks to find the probability that the first three tosses of the pair of dices
will do not get a 6, while the 4-th toss will get 6.
This probability is P = = = 0.088684 (approximately). ANSWER
Solved.
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On tossing a pair of dices, see the lesson
- Rolling a pair of fair dice
in this site. You will find there many other similar solved problems.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Solved problems on Probability".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.